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GATE | GATE-CS-2014-(Set-1) | Question 65

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Consider a 4-to-1 multiplexer with two select lines S1 and S0, given below GATECS2014Q55 The minimal sum-of-products form of the Boolean expression for the output F of the multiplexer is (A) P’Q + QR’ + PQ’R (B) P’Q + P’QR’ + PQR’ + PQ’R (C) P’QR + P’QR’ + QR’ + PQ’R (D) PQR’

Answer: (A)

Explanation: For 4 to 1 mux =p’q’(0)+p’q(1)+pq’r+pqr’ =p’q+pq’r+pqr’ =q(p’+pr’)+pq’r =q(p’+r’)+pq’r =p’q+qr’+pq’r Ans (a)

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Last Updated : 29 Sep, 2021
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