# GATE | GATE-CS-2007 | Question 4

Let G be the non-planar graph with the minimum possible number of edges. Then G has

(A)

10 edges and 6 vertices

(B)

10 edges and 5 vertices

(C)

9 edges and 6 vertices

(D)

9 edges and 5 vertices

Explanation:

According to Kuratowski\’s Theorem, a graph is planar if and only if it does not contain any subdivisions of the graphs K5 or K3,3

That means K5 and K3,3 are minimum non-planar graphs. These graphs have 5 vertices with 10 edges in K5 and 6 vertices with 9 edges in K3,3 graph.
So, graph K5 has minimum vertices and maximum edges than K3,3

Alternative method:
A plane graph having â€˜nâ€™ vertices, cannot have more than â€˜2*n-4â€™ number of edges. Hence using the logic we can derive that for 6 vertices, 8 edges is required to make it a plane graph. So adding one edge to the graph will make it a non planar graph.

So, 6 vertices and 9 edges is the correct answer.

So, option (B) is correct.

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