Finding the Ceiling Value of Specified Number in Golang

Last Updated : 01 Apr, 2020

Go language provides inbuilt support for basic constants and mathematical functions to perform operations on the numbers with the help of the math package. You are allowed to find the least integer value greater than or equal to the specified number with the help of the Ceil() function provided by the math package. So, you need to add a math package in your program with the help of the import keyword to access the Ceil() function.

Syntax:

func Ceil(y float64) float64

If you pass +Inf or -Inf in this function, then this function will return +Inf or -Inf.
If you pass -0 or +0 in this function, then this function will return -0 or +0.
If you pass NaN in this function, then this function will return NaN.

Example 1:

// Golang program to illustrate how to find
// the least integer value greater than or
// equal to the specified number
package main
  
import (
    "fmt"
    "math"
)
  
// Main function
func main() {
  
    // Finding the least integer value 
    // greater than or equal to the
    // given number
    // Using Ceil() function
    res_1 := math.Ceil(math.Pi / 2)
    res_2 := math.Ceil(34.567)
    res_3 := math.Ceil(-12.34)
  
    // Displaying the result
    fmt.Printf("Result 1: %.1f", res_1)
    fmt.Printf("\nResult 2: %.1f", res_2)
    fmt.Printf("\nResult 3: %.1f", res_3)
  
}

Output:

Result 1: 2.0
Result 2: 35.0
Result 3: -12.0

Example 2:

// Golang program to illustrate how to find
// the least integer value greater than or
// equal to the specified number
package main
  
import (
    "fmt"
    "math"
)
  
// Main function
func main() {
  
    // Finding the least integer value
    // greater than or equal to the
    // given number
    nvalue_1 := math.Sin(math.Pi / 4)
    nvalue_2 := math.Sin(math.Pi / 6)
    res := nvalue_1 + nvalue_2
      
    fmt.Printf("%.1f + %.1f = %.1f",
            nvalue_1, nvalue_2, res)
    fmt.Println("\nRound off the result: ",
                            math.Ceil(res))
  
}

Output:

0.7 + 0.5 = 1.2
Round off result:  2

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