Given an array arr of size N. The task is to find the sum of the first half (N/2) elements and second half elements (N – N/2) of an array.
Examples:
Input : arr[] = {20, 30, 60, 10, 25, 15, 40}
Output : 110, 90
Sum of first N/2 elemets 20 + 30 + 60 is 110Input : arr[] = {50, 35, 20, 15}
Output : 85, 35
Approach:
Initialize SumFirst and SumSecond as 0. Traverse the given array and add elements in SumFirst if the current index is less than N/2 otherwise add in SumSecond.
Below is the implementation of the above approach:
C++
// C++ program to find the sum of the first half // elements and second half elements of an array #include <bits/stdc++.h> using namespace std; // Function to find the sum of the first half // elements and second half elements of an array void sum_of_elements(int arr[], int n) { int sumfirst = 0, sumsecond = 0; for (int i = 0; i < n; i++) { // Add elements in first half sum if (i < n / 2) sumfirst += arr[i]; // Add elements in the second half sum else sumsecond += arr[i]; } cout << "Sum of first half elements is " << sumfirst << endl; cout << "Sum of second half elements is " << sumsecond << endl; } // Driver Code int main() { int arr[] = { 20, 30, 60, 10, 25, 15, 40 }; int n = sizeof(arr) / sizeof(arr[0]); // Function call sum_of_elements(arr, n); return 0; } |
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Java
// Java program to count pairs // whose sum divisible by 'K' import java.util.*; class GFG { public static void sum_of_elements(int []arr, int n) { int sumfirst = 0, sumsecond = 0; for (int i = 0; i < n; i++) { // Add elements in first half sum if (i < n / 2) { sumfirst += arr[i]; } // Add elements in the second half sum else { sumsecond += arr[i]; } } System.out.println("Sum of first half elements is " + sumfirst); System.out.println("Sum of second half elements is " + sumsecond); } // Driver code public static void main(String[] args) { int []arr = { 20, 30, 60, 10, 25, 15, 40 }; int n = arr.length; // Function call sum_of_elements(arr, n); } } // This code is contributed by Princi Singh |
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Python3
# Python3 program to find the sum of # the first half elements and # second half elements of an array # Function to find the sum of # the first half elements and # second half elements of an array def sum_of_elements(arr, n): sumfirst = 0; sumsecond = 0; for i in range(n): # Add elements in first half sum if (i < n // 2): sumfirst += arr[i]; # Add elements in the second half sum else: sumsecond += arr[i]; print("Sum of first half elements is", sumfirst, end = "\n"); print("Sum of second half elements is", sumsecond, end = "\n"); # Driver Code arr = [20, 30, 60, 10, 25, 15, 40]; n = len(arr); # Function call sum_of_elements(arr, n); # This code is contributed # by Akanksha Rai |
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C#
// C# program to count pairs // whose sum divisible by 'K' using System; class GFG { public static void sum_of_elements(int []arr, int n) { int sumfirst = 0, sumsecond = 0; for (int i = 0; i < n; i++) { // Add elements in first half sum if (i < n / 2) { sumfirst += arr[i]; } // Add elements in the second half sum else { sumsecond += arr[i]; } } Console.WriteLine("Sum of first half elements is " + sumfirst); Console.WriteLine("Sum of second half elements is " + sumsecond); } // Driver code static public void Main () { int []arr = { 20, 30, 60, 10, 25, 15, 40 }; int n = arr.Length; // Function call sum_of_elements(arr, n); } } // This code is contributed by nidhiva |
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Output:
Sum of first half elements is 110 Sum of second half elements is 90
Time complexity: O(N)
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