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Find temperature of missing days using given sum and average
• Difficulty Level : Basic
• Last Updated : 01 Apr, 2021

Given integers x and y which denotes the average temperature of the week except for days Day1 and Day2 respectively, and the sum of the temperature of Day1 and Day2 as S, the task is to find the temperature of the days Day1 and Day2.
Examples:

Input: x = 15, y = 10, S = 50
Output: Day1 = 10, Day2 = 40
Explanation:
The average of week excluding Day1 is 15, the average of week excluding Day2 is 10 and the sum of temperature of Day1 and Day2 is 50. Individual temperature of the two days are 10 and 40 respecticvely.
Input: x = 5, y = 10, s = 40
Output: Day1 = 35, Day2 = 5
Explanation:
The average of week excluding Day1 is 5, the average of week excluding Day2 is 10 and the sum of temperature of Day1 and Day2 is 40. Individual temperature of the two days are 35 and 5 respecticvely.

Approach: We know that Average = sum of all observation / total number of observation. Hence, the sum of observation = Average * number of observation i.e., S = A * n

So after excluding Day1 or Day2 we are left with only 6 days
so N = 6 and the equations are: and on subtracting the above two equations we get, (Equation 1)
and it is given in the problem statement that (Equation 2)

Solving the above two equations, the value of Day1 and Day2 is given by: [Tex]Day1 = S – Day2  [/Tex]

Below is the implementation of above approach:

## C++

 // C++ program for the above approach #include using namespace std; // Function for finding the temperaturevoid findTemperature(int x, int y, int s){    double Day1, Day2;     // Store Day1 - Day2 in diff    double diff = (x - y) * 6;     Day2 = (diff + s) / 2;     // Remaining from s will be Day1    Day1 = s - Day2;     // Print Day1 and Day2    cout << "Day1 : " << Day1 << endl;    cout << "Day2 : " << Day2 << endl;} // Driver Codeint main(){    int x = 5, y = 10, s = 40;     // Functions    findTemperature(x, y, s);     return 0;}

## Java

 // Java program for the above approachclass GFG{  // Function for finding the temperaturestatic void findTemperature(int x, int y, int s){    double Day1, Day2;      // Store Day1 - Day2 in diff    double diff = (x - y) * 6;      Day2 = (diff + s) / 2;      // Remaining from s will be Day1    Day1 = s - Day2;      // Print Day1 and Day2    System.out.println( "Day1 : " + Day1);    System.out.println( "Day2 : " + Day2);}  // Driver Codepublic static void main(String[] args){    int x = 5, y = 10, s = 40;      // Functions    findTemperature(x, y, s);}} // This code is contributed by rock_cool

## Python

 # Python3 program for the above approach # Function for finding the temperaturedef findTemperature(x, y, s):     # Store Day1 - Day2 in diff    diff = (x - y) * 6    Day2 = (diff + s) // 2     # Remaining from s will be Day1    Day1 = s - Day2     # Print Day1 and Day2    print("Day1 : ", Day1)    print("Day2 : ", Day2) # Driver Codeif __name__ == '__main__':    x = 5    y = 10    s = 40     # Functions    findTemperature(x, y, s) # This code is contributed by Mohit Kumar

## C#

 // C# program for the above approachusing System;class GFG{   // Function for finding the temperaturestatic void findTemperature(int x, int y, int s){    double Day1, Day2;       // Store Day1 - Day2 in diff    double diff = (x - y) * 6;       Day2 = (diff + s) / 2;       // Remaining from s will be Day1    Day1 = s - Day2;       // Print Day1 and Day2    Console.Write( "Day1 : " + Day1 + '\n');    Console.WriteLine( "Day2 : " + Day2 + '\n');}   // Driver Codepublic static void Main(string[] args){    int x = 5, y = 10, s = 40;       // Functions    findTemperature(x, y, s);}} // This code is contributed by Ritik Bansal

## Javascript

 

Output:
Day1 : 35
Day2 : 5

Time Complexity: O(1)
Auxiliary Space: O(1)

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