D3.js | d3.timeSaturdays() Function
Last Updated :
23 Jul, 2019
The d3.timeSaturdays() function in D3.js is used to return all the dates based on Saturday in the given range of start and end date.
Syntax:
d3.timeSaturdays(start, end, step);
Parameters: This function accept three parameters which are given below:
- Start: This is the given start date.
- end: This is the given end date.
- step: This is the optional value used to skip dates.
Return Value: This function returns all the dates based on Saturday.
Below programs illustrate the d3.timeSaturdays() function in D3.js:
Example 1:
<!DOCTYPE html>
<html>
<head>
<title>
D3.js | d3.timeSaturdays() Function
</title>
<script src=
</script>
</head>
<body>
<script>
var start = new Date(2015, 07, 01);
var end = new Date(2015, 07, 30);
var a = d3.timeSaturdays(start, end);
console.log(a);
</script>
</body>
</html>
|
Output:
[“2015-07-31T18:30:00.000Z”, “2015-08-07T18:30:00.000Z”, “2015-08-14T18:30:00.000Z”, “2015-08-21T18:30:00.000Z”, “2015-08-28T18:30:00.000Z”]
Example 2:
<!DOCTYPE html>
<html>
<head>
<title>
D3.js | d3.timeSaturdays() Function
</title>
<script src=
</script>
</head>
<body>
<script>
var start = new Date(2015, 07, 01);
var end = new Date(2015, 07, 30);
var a = d3.timeSaturdays(start, end, 2);
console.log(a);
</script>
</body>
</html>
|
Output:
["2015-07-31T18:30:00.000Z", "2015-08-14T18:30:00.000Z", "2015-08-28T18:30:00.000Z"]
Reference: https://devdocs.io/d3~5/d3-time#timeSaturdays
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