D3.js | d3.timeDays() Function

The d3.timeDays() function in D3.js is used to return all the dates in between two given dates.

Syntax:

d3.timeDays(Start, End, step);

Parameters: This function accept three parameters which are given below:



  • Start: This is the given start date.
  • End: This is the given end date.
  • step: This parameter is optional and used to skip the dates.

Return Value: This function returns all the dates in between two given dates.

Below programs illustrate the d3.timeDays() function in D3.js:

Example 1:

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<!DOCTYPE html>
<html>
  
<head>
    <script src="https://d3js.org/d3.v4.min.js">
  </script>
</head>
  
<body>
  
    <script>
        // Initialising start and end date
        var start = new Date(2015, 04, 05);
        var end = new Date(2015, 04, 10);
  
        // Calling the timeDays() function
        // without step value
        var a = d3.timeDays(start, end);
  
        // Getting all the in between dates
        console.log(a);
    </script>
</body>
  
</html>

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Output:

[“2015-05-04T18:30:00.000Z”,”2015-05-05T18:30:00.000Z”,”2015-05-06T18:30:00.000Z”,”2015-05-07T18:30:00.000Z”,”2015-05-08T18:30:00.000Z”]

Example 2:

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<!DOCTYPE html>
<html>
  
<head>
    <script src="https://d3js.org/d3.v4.min.js">
  </script>
</head>
  
<body>
  
    <script>
        // Initialising start and end date
        var start = new Date(2015, 04, 05);
        var end = new Date(2015, 04, 08);
  
        // Calling the timeDays() function
        // with step value
        var a = d3.timeDays(start, end, 2);
  
        // Getting all the in between dates
        console.log(a);
    </script>
</body>
  
</html>

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Output:

["2015-05-04T18:30:00.000Z","2015-05-06T18:30:00.000Z"]

Reference: https://devdocs.io/d3~5/d3-time#timeDays



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