D3.js | d3.max() function

The d3.max() function in D3.js is used to returns the maximum value in the given array using natural order. If an array is empty then it returns undefined as output.

Syntax:

d3.max(Array)

Parameters: This function accepts a parameters Array which is an array of elements whose maximum value is to be calculated. Here elements might be integers or any strings.

Return Value: It returns the maximum value.

Below programs illustrate the d3.max() function in D3.js.
Example 1:

<html> 
  
<head> 
    <title>Getting maximum value</title> 
</head> 
  
<body> 
    <script src='https://d3js.org/d3.v4.min.js'> 
  </script> 
  
    <script> 
        // initialising the array of elements 
        var Array1 = [10, 20, 30, 40, 50, 60]; 
        var Array2 = [1, 2]; 
        var Array3 = [0, 1.5, 6.8]; 
        var Array4 = [.8, .08, .008]; 
  
        // Calling to d3.max() function 
        A = d3.max(Array1); 
        B = d3.max(Array2); 
        C = d3.max(Array3); 
        D = d3.max(Array4); 
  
        // Getting maximum value 
        document.write(A + "<br>"); 
        document.write(B + "<br>"); 
        document.write(C + "<br>"); 
        document.write(D + "<br>"); 
    </script> 
</body> 
  
</html> 

Output:

Example 2:

<html> 
  
<head> 
    <title>Getting maximum value</title> 
</head> 
  
<body> 
    <script src='https://d3js.org/d3.v4.min.js'> 
  </script> 
  
    <script> 
        // initialising the array of elements 
        var Array1 = []; 
        var Array2 = ["a", "b", "c"]; 
        var Array3 = ["A", "B", "C"]; 
        var Array4 = ["Geek", "Geeks", "GeeksforGeeks"]; 
  
        // Calling to d3.max() function 
        A = d3.max(Array1); 
        B = d3.max(Array2); 
        C = d3.max(Array3); 
        D = d3.max(Array4); 
  
        // Getting maximum value 
        document.write(A + "<br>"); 
        document.write(B + "<br>"); 
        document.write(C + "<br>"); 
        document.write(D + "<br>"); 
    </script> 
</body> 
  
</html> 

Output:

undefined
c
C
GeeksforGeeks

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