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C++ Program To Print Number Pattern

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  • Difficulty Level : Easy
  • Last Updated : 04 Aug, 2022

Here, we will see a C++ program to print the 3 different number patterns. There are 3 number patterns covered using for loop and while loop with their respective explanation.
3 Different Number Patterns:

1                                               
2 3 
4 5 6 
7 8 9 10 
11 12 13 14 15         


1
2 2 
3 3 3
4 4 4 4
5 5 5 5 5 


1
12
123
1234
12345

Pattern 1:

Input: n = 5
 
Output: 

1 
2 3 
4 5 6 
7 8 9 10 
11 12 13 14 15  

Using for loop:

The first for loop is used to iterate the number of rows and the second for loop is used to repeat the number of columns. Then print the number and increment the number to print the next number.

C++




// C++ program to print number patterns using for loop
#include <iostream>
using namespace std;
 
int main()
{
    int rows, columns, number = 1, n = 5;
   
    // first for loop is used to identify number of rows
    for (rows = 0; rows <= n; rows++) {
       
        // second for loop is used to identify number of
        // columns and here the values will be changed
        // according to the first for loop
        for (columns = 0; columns < rows; columns++) {
           
            // printing number pattern based on the number
            // of columns
            cout << number << " ";
           
            // incrementing number at each column to print
            // the next number
            number++;
        }
       
        // print the next line for each row
        cout << "\n";
    }
    return 0;
}

Output

1 
2 3 
4 5 6 
7 8 9 10 
11 12 13 14 15 

Time Complexity: O(n2)

Auxiliary Space: O(1)

Using while loop:

The while loops check the condition until the condition is false. If the condition is true then enter into the loop and execute the statements.

C++




// C++ program to print number
// patterns using while loop
#include <iostream>
using namespace std;
 
int main()
{
    int rows = 1, columns = 0, n = 5;
 
    // 1 value is assigned to the number
    // helpful to print the number patter
    int number = 1;
 
    // while loops check the condition and repeat
    // the loop until the condition is false
    while (rows <= n) {
        while (columns <= rows - 1) {
 
            // printing number to get required pattern
            cout << number << " ";
 
            // incrementing columns value
            columns++;
 
            // incrementing number value to
            // print the next number
            number++;
        }
        columns = 0;
       
        // incrementing rows value
        rows++;
        cout << endl;
    }
    return 0;
}

Output

1 
2 3 
4 5 6 
7 8 9 10 
11 12 13 14 15 

Time Complexity: O(n2)

Auxiliary Space: O(1)

Pattern 2:

Input: n = 5

Output:  

1
2 2 
3 3 3
4 4 4 4
5 5 5 5 5 

Using for loop:

The first for loop is used to iterate the number of rows and the second for loop is used to repeat the number of columns. Then print the row number to get the required output.

C++




// C++ program to print number
// patterns using for loop
#include <iostream>
using namespace std;
 
int main()
{
    int rows, columns, n = 5;
 
    // first for loop is used to
    // identify number of rows
    for (rows = 1; rows <= n; rows++) {
 
        // second for loop is used to identify number of
        // columns and here the values will be changed
        // according to the first for loop
        for (columns = 1; columns <= rows; columns++) {
 
            // printing number pattern based on the number
            // of rows
            cout << rows << " ";
        }
        // print the next line for each row
        cout << "\n";
    }
    return 0;
}

Output

1 
2 2 
3 3 3 
4 4 4 4 
5 5 5 5 5 

Time Complexity: O(n2)

Auxiliary Space: O(1)

Using while loop: 

The while loops check the condition until the condition is false. If the condition is true then enter into the loop and execute the statements.

C++




// C++ program to print number
// patterns using while loop
#include <iostream>
using namespace std;
 
int main()
{
    int rows = 1, columns = 0, n = 5;
   
    // while loops check the condition and repeat
    // the loop until the condition is false
    while (rows <= n) {
       
        while (columns <= rows - 1) {
           
            // printing number to get required pattern
            cout << rows << " ";
           
            // incrementing columns value
            columns++;
        }
        columns = 0;
       
        // incrementing rows value
        rows++;
       
        cout << endl;
    }
    return 0;
}

Output

1 
2 2 
3 3 3 
4 4 4 4 
5 5 5 5 5 

Time Complexity: O(n2)

Auxiliary Space: O(1)

Pattern 3:

Input: n = 5

Output: 

1
12
123
1234
12345

Using for loop:

The first for loop is used to iterate the number of rows and the second for loop is used to repeat the number of columns. Then print the column number to get the required output.

C++




// C++ program to print number
// patterns using for loop
#include <iostream>
using namespace std;
 
int main()
{
    int rows, columns, n = 5;
   
    // second for loop is used to identify number of rows
    for (rows = 1; rows <= n; rows++) {
       
        // second for loop is used to identify number of
        // columns and here the values will be changed
        // according to the first for loop
        for (columns = 1; columns <= rows; columns++) {
           
            // print the number to be print based on the
            // number of columns
            cout << columns << " ";
        }
        // print the next line
        cout << "\n";
    }
    return 0;
}

Output

1 
1 2 
1 2 3 
1 2 3 4 
1 2 3 4 5 

Time Complexity: O(n2)

Auxiliary Space: O(1)

Using while loop: 

The while loops check the condition until the condition is false. If condition is true then enter into loop and execute the statements.

C++




// C++ program to print number
// patterns using while loop
#include <iostream>
using namespace std;
 
int main()
{
    int rows = 1, columns = 1, n = 6;
    int number = 1;
   
    // while loops check the condition and repeat
    // the loop until the condition is false
    while (rows <= n) {
       
        while (columns <= rows - 1) {
           
            // printing number to get required pattern
            cout << columns << " ";
           
            // incrementing columns value
            columns++;
        }
        columns = 1;
       
        // incrementing rows value
        rows++;
        cout << endl;
    }
    return 0;
}

Output

1 
1 2 
1 2 3 
1 2 3 4 
1 2 3 4 5 

Time Complexity: O(n2)

Auxiliary Space: O(1)


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