C# Program to Check a Specified Type is an Interface or not

The interface is just like a class, it can also have methods, properties, events, etc. as its members, but it only contains the declaration of the members and the implementation of these members will be given by the class that implements the interface implicitly or explicitly. We can check the specified type is an interface or not by using the IsInterface property of the Type class. It will return true if the given type is an interface. Otherwise, it will return false. It is a read-only property.

Syntax:

public bool IsInterface { get; }

Example 1:

C#

// C# program to check whether the
// given type is interface or not
using System;
using System.Reflection;

// Declare an interface
interface myinterface
{

    // Method in interface
    void gfg();
}

class GFG{

// Driver code
static void Main()
{

    // Check the type is interface or not
    // Using the IsInterface property
    if (typeof(myinterface).IsInterface == true)
    {
        Console.WriteLine("Yes it is Interface");
    }
    else
    {
        Console.WriteLine("No it is not an Interface");
    }
}
}

Output:

Yes it is Interface

Example 2:

C#

// C# program to check whether the
// given type is interface or not
using System;
using System.Reflection;

// Declare an interface
interface myinterface
{

    // Method in interface
    void gfg();
}

// Declare a class
public class myclass
{
    public void myfunc(){}
}

// Declare a struct
public struct mystruct
{
    int a;
}

class GFG{

// Driver code
static void Main()
{

    // Check the type is interface or not
    // Using the IsInterface property
    Console.WriteLine(typeof(myinterface).IsInterface);
    Console.WriteLine(typeof(myclass).IsInterface);
    Console.WriteLine(typeof(mystruct).IsInterface);
}
}

Output:

True
False
False