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C++ | Inheritance | Question 1
  • Difficulty Level : Easy
  • Last Updated : 21 Aug, 2013




#include<iostream>
   
using namespace std;
class Base1 {
 public:
     Base1()
     { cout << " Base1's constructor called" << endl;  }
};
   
class Base2 {
 public:
     Base2()
     { cout << "Base2's constructor called" << endl;  }
};
   
class Derived: public Base1, public Base2 {
   public:
     Derived()
     {  cout << "Derived's constructor called" << endl;  }
};
   
int main()
{
   Derived d;
   return 0;
}

(A) Compiler Dependent


(B) Base1′s constructor called
Base2′s constructor called
Derived’s constructor called


(C) Base2′s constructor called
Base1′s constructor called
Derived’s constructor called


(D) Compiler Error


Answer: (B)

Explanation: When a class inherits from multiple classes, constructors of base classes are called in the same order as they are specified in inheritance.

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