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UGC-NET | UGC NET CS 2014 Dec - II | Question 35
The following Context-Free Grammar (CFG): S → aB | bA A → a | aS | bAA B → b | bS | aBB will generate (1) odd numbers of a’s and odd numbers of b’s (2) even numbers of a’s and even numbers of b’s (3) equal numbers of a’s and b’s (4) different numbers of a’s and b’s
(A)
(1)
(B)
(2) an (3)
(C)
(1), (2) and (3)
(D)
All are correct.
Answer
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