# Time until distance gets equal to X between two objects moving in opposite direction

Consider two people moving in opposite direction with speeds U meters/second and V meters/second respectively. The task is to find how long will take to make the distance between them X meters.
Examples:

Input: U = 3, V = 3, X = 3
Output: 0.5
After 0.5 seconds, policeman A will be at distance 1.5 meters
and policeman B will be at distance 1.5 meters in the opposite direction
The distance between the two policemen is 1.5 + 1.5 = 3
Input: U = 5, V = 2, X = 4
Output: 0.571429

Approach: It can be solved using distance = speed * time. Here, distance would be equal to the given range i.e. distance = X and speed would be the sum of the two speeds because they are moving in the opposite direction i.e. speed = U + V.
Below is the implementation of the above approach:

## C++

 `// C++ implementation of the approach``#include ``using` `namespace` `std;` `// Function to return the time for which``// the two policemen can communicate``double` `getTime(``int` `u, ``int` `v, ``int` `x)``{``    ``double` `speed = u + v;` `    ``// time = distance / speed``    ``double` `time` `= x / speed;``    ``return` `time``;``}` `// Driver code``int` `main()``{``    ``double` `u = 3, v = 3, x = 3;``    ``cout << getTime(u, v, x);` `    ``return` `0;``}`

## Java

 `// Java implementation of the approach``class` `GFG ``{` `    ``// Function to return the time for which``    ``// the two policemen can communicate``    ``static` `double` `getTime(``int` `u, ``int` `v, ``int` `x) ``    ``{``        ``double` `speed = u + v;` `        ``// time = distance / speed``        ``double` `time = x / speed;``        ``return` `time;``    ``}` `    ``// Driver code``    ``public` `static` `void` `main(String[] args) ``    ``{``        ``int` `u = ``3``, v = ``3``, x = ``3``;``        ``System.out.println(getTime(u, v, x));``    ``}``}` `/* This code contributed by PrinciRaj1992 */`

## Python3

 `# Python3 implementation of the approach ` `# Function to return the time ``# for which the two policemen ``# can communicate ``def` `getTime(u, v, x): ` `    ``speed ``=` `u ``+` `v ` `    ``# time = distance / speed ``    ``time ``=` `x ``/` `speed ``    ``return` `time ` `# Driver code ``if` `__name__ ``=``=` `"__main__"``:` `    ``u, v, x ``=` `3``, ``3``, ``3``    ``print``(getTime(u, v, x)) ` `# This code is contributed``# by Rituraj Jain`

## C#

 `// C# implementation of the approach``using` `System;` `class` `GFG ``{` `    ``// Function to return the time for which``    ``// the two policemen can communicate``    ``static` `double` `getTime(``int` `u, ``int` `v, ``int` `x) ``    ``{``        ``double` `speed = u + v;` `        ``// time = distance / speed``        ``double` `time = x / speed;``        ``return` `time;``    ``}` `    ``// Driver code``    ``public` `static` `void` `Main() ``    ``{``        ``int` `u = 3, v = 3, x = 3;``        ``Console.WriteLine(getTime(u, v, x));``    ``}``}` `// This code is contributed``// by Akanksha Rai`

## PHP

 ``

## Javascript

 ``

Output:
`0.5`

Time Complexity: O(1)
Auxiliary Space: O(1)

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