QA – Placement Quizzes  Mixtures and Alligation  Question 9
A vessel full of orange juice contains 40% orange pulp. A part of juice is replaced by another juice containing 19% orange pulp and now the percentage of orange pulp is found to be 26%. What quantity of juice is replaced?
(A) 3:2
(B) 5:4
(C) 4:5
(D) 2:3
Answer: (D)
Explanation: Concentration of orange pulp in 1^{st} vessel = 40%
Concentration of orange pulp in 2^{nd} vessel = 19%
After the mixing, Concentration of orange pulp in the mixture = 26%
By rule of alligation,
Concentration of orange pulp in 1st vessel 
Concentration of orange pulp in 2nd vessel 

40% 
19% 

26% 

2619=7 
4026=14 
Hence ratio of 1^{st} and 2^{nd} quantities = 7 : 14 = 1 : 2
i.e., 2/(1+2)=2/3 part of the juice is replaced.
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