A linked list L0 -> L1 -> L2 -> ….. -> LN can be folded as L0 -> LN -> L1 -> LN – 1 -> L2 -> …..
Given a folded linked list, the task is to unfold and print the original linked list
Input: 1 -> 6 -> 2 -> 5 -> 3 -> 4
Output: 1 2 3 4 5 6
Input: 1 -> 5 -> 2 -> 4 -> 3
Output: 1 2 3 4 5
Approach: Make a recursive call and store the next node in temp pointer, first node will act as head node and the node which is stored in temp pointer will act as a tail of the list. On returning after reaching the base condition link the head and tail to previous head and tail respectively.
Base condition: If number of nodes is even then the second last node is head and the last node is tail and if the number of nodes is odd then last node will act as head as well as tail.
Below is the implementation of the above approach:
1 5 2 4 3 1 2 3 4 5
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Improved By : princiraj1992