# Power Function in C/C++

• Difficulty Level : Easy
• Last Updated : 17 Sep, 2022

Given two numbers base and exponent, pow() function finds x raised to the power of y i.e. xy. Basically in C exponent value is calculated using the pow() function. pow() is function to get the power of a number, but we have to use #include<math.h> in c/c++  to use that pow() function.  then two numbers are passed. Example – pow(4 , 2); Then we will get the result as 4^2, which is 16.
Example:

```Input: 2.0, 5.0
Output: 32
Explanation:
pow(2.0, 5.0) executes 2.0 raised to
the power 5.0, which equals 32

Input: 5.0, 2.0
Output: 25
Explanation:
pow(5.0, 2.0) executes 5.0 raised to
the power 2.0, which equals 25```

Syntax:

`double pow(double x, double y);`

Parameters: The method takes two arguments:

• x : floating point base value
• y : floating point power value

Program:

## C

 `// C program to illustrate``// power function``#include ``#include ` `int` `main()``{``    ``double` `x = 6.1, y = 4.8;` `    ``// Storing the answer in result.``    ``double` `result = ``pow``(x, y);``    ``printf``(``"%.2lf"``, result);` `    ``return` `0;``}`

## C++

 `// CPP program to illustrate``// power function``#include ``using` `namespace` `std;` `int` `main()``{``    ``double` `x = 6.1, y = 4.8;` `    ``// Storing the answer in result.``    ``double` `result = ``pow``(x, y);` `    ``// printing the result upto 2``    ``// decimal place``    ``cout << fixed << setprecision(2) << result << endl;` `    ``return` `0;``}`

Output:

`5882.79`

Time Complexity: O(log(n))

Auxiliary Space: O(1)

Working of pow() function with integers

The pow() function takes ‘double’ as the arguments and returns a ‘double’ value. This function does not always work for integers. One such example is pow(5, 2). When assigned to an integer, it outputs 24 on some compilers and works fine for some other compilers. But pow(5, 2) without any assignment to an integer outputs 25.

One another way can be using the round function to assign it to some integer type.

• This is because 52 (i.e. 25) might be stored as 24.9999999 or 25.0000000001 because the return type is double. When assigned to int, 25.0000000001 becomes 25 but 24.9999999 will give output 24.
• To overcome this and output the accurate answer in integer format, we can add 1e-9 or 0.000000001 to the result and typecast it to int e.g (int)(pow(5, 2)+1e-9) will give the correct answer(25, in above example), irrespective of the compiler.

## C

 `// C program to illustrate``// working with integers in``// power function``#include ``#include ` `int` `main()``{``    ``int` `a, b;` `    ``// Using typecasting for``    ``// integer result``    ``a = (``int``)(``pow``(5, 2) + 1e-9);``    ``b = round(``pow``(5,2));``    ``printf``(``"%d \n%d"``, a, b);` `    ``return` `0;``}`

## C++

 `// CPP program to illustrate``// working with integers in``// power function``#include ``using` `namespace` `std;``int` `main()``{``    ``int` `a, b;` `    ``// Using typecasting for``    ``// integer result``    ``a = (``int``)(``pow``(5, 2) + 0.5);``    ``b = round(``pow``(5,2));``    ``cout << a << endl << b ;` `    ``return` `0;``}`

```Output:
25
25```

Time Complexity: O(log(n))

Auxiliary Space: O(1)

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