NTA | UGC NET 2019 June – II | Question 68
Match List-I with List-II:
(a) Greedy best-first (i) Minimal cost (p)+h(p)
(b) Lowest cost-first (ii) Minimal h(p)
(c) A* algorithm (iii) Minimal cost (p)
Choose the correct option from those given below:
(a) – (i) ; (b) – (ii); (c) – (iii)
(a) – (iii) ; (b) – (ii); (c) – (i)
(a) – (i) ; (b) – (iii); (c) – (ii)
(a) – (ii) ; (b) – (iii); (c) – (i)
Greedy best first: Minimal h(p)
Lowest cost: Minimal cost(p)
A* search: Minimal cost(p)+h(p) where,
=> g = the movement cost to move from the starting point to a given square on the grid, following the path generated to get there.
=> h = the estimated movement cost to move from that given square on the grid to the final destination. This is often referred to as the heuristic,
So, option D is correct.
Quiz of this Question
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