Java Math subtractExact(int a , int b) method
Last Updated :
04 Apr, 2023
The java.lang.Math.subtractExact() is a built-in math function in java that returns the difference of the arguments. It throws an exception if the result overflows an int. As subtractExact(int a, int b) is static, so object creation is not required.
Syntax:
public static int subtractExact(int a, int b)
Parameters:
- a: the first value
- b: the second value to be subtracted from the first
Return Type: This method returns the difference between the arguments.
Exception: It throws ArithmeticException – if the result overflows an int
Example: To show the working of java.lang.Math.subtractExact() method.
java
import java.lang.Math;
class Gfg1 {
public static void main(String args[])
{
int a = 300 ;
int b = 200 ;
System.out.println(Math.subtractExact(a, b));
}
}
|
Example:
java
import java.lang.Math;
class Gfg2 {
public static void main(String args[])
{
int x = Integer.MIN_VALUE;
int y = 10 ;
System.out.println(Math.subtractExact(x, y));
}
}
|
Output:
Runtime Error:
Exception in thread "main" java.lang.ArithmeticException: integer overflow
at java.lang.Math.subtractExact(Math.java:829)
at Gfg2.main(File.java:13)
Example:
Java
class A {
public static void main(String[] args)
{
int a = 5 ;
int b = 3 ;
int result = Math.subtractExact(a, b);
System.out.println( "The difference of " + a
+ " and " + b + " is " + result);
}
}
|
Output
The difference of 5 and 3 is 2
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