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ISRO | ISRO CS 2016 | Question 4

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The minimum number of NAND gates required to implement the Boolean function A + AB’+ AB’C is equal to
(A) 0
(B) 1
(C) 4
(D) 7

Answer: (A)

Explanation: A + AB’+ AB’C
=A(1+B’) + AB’C
=A + AB’C
So, no extra gate is required. Correct option is (A)

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Last Updated : 22 Mar, 2018
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