Integer decode() Method in Java

It is often seen that any integer within (” “) is also considered as string, then it is needed to decode that into the integer. The main function of java.lang.Integer.decode() method is to decode a String into an Integer. The method also accepts decimal, hexadecimal, and octal numbers.

Syntax :

public static Integer decode(String str)

Parameters: The method takes one parameter str of String data type and refers to the string needed to decode.



Return Value: This method returns an Integer object which holds the int value represented by the string str.

Exception: The method throws NumberFormatException, when the String contains an integer that cannot be parsed.

Examples:

Input: str_value = "50"
Output: 50

Input: str_value = "GFG"
Output: NumberFormatException

Below programs illustrate the java.lang.Integer.decode() method.
Program 1:

filter_none

edit
close

play_arrow

link
brightness_4
code

// Java program to demonstrate working
// of java.lang.Integer.decode() method
import java.lang.*;
  
public class Gfg {
  
    public static void main(String[] args)
    {
  
        Integer int1 = new Integer(22);
        // string here given the value of 65
        String nstr = "65";
  
        // Returns an Integer object holding the int value
        System.out.println("Actual Integral Number = "+
        int1.decode(nstr));
    }
}

chevron_right


Output:

Actual Integral Number = 65

Program 2: When string value is passed a NumberFormatException is thrown.

filter_none

edit
close

play_arrow

link
brightness_4
code

// Java program to demonstrate working
// of java.lang.Integer.decode() method
import java.lang.*;
  
public class Gfg {
  
    public static void main(String[] args)
    {
  
        Integer int1 = new Integer(22);
  
        // String here passed as "geeksforgeeks"
        String nstr = "geeksforgeeks";
  
        System.out.println("Actual Integral Number = ");
        System.out.println(int1.decode(nstr));
    }
}

chevron_right


Output:

Exception in thread "main" java.lang.NumberFormatException: For input string: "geeksforgeeks"
    at java.lang.NumberFormatException.forInputString(NumberFormatException.java:65)
    at java.lang.Integer.parseInt(Integer.java:580)
    at java.lang.Integer.valueOf(Integer.java:740)
    at java.lang.Integer.decode(Integer.java:1197)
    at Gfg.main(Gfg.java:15)


My Personal Notes arrow_drop_up

lets make it a lil simple

If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.

Please Improve this article if you find anything incorrect by clicking on the "Improve Article" button below.