Why operator overloading?
Let’s say we have defined a class Integer for handling operations on integers. We can have functions add(), subtract(), multiply() and divide() for handling the respective operations. However, to make the code more intuitive and enhance readability, it is preferred to use operators that correspond to the given operations(+, -, *, / respectively) i.e. we can replace the following code
Replace i5 = divide(add(i1, i2), subtract(i3, i4)) by a simpler code: i5 = (i1 + i2) / (i3 - i4)
Overloading the increment operator
The operator symbol for both prefix(++i) and postfix(i++) are the same. Hence, we need two different function definitions to distinguish between them. This is achieved by passing a dummy int parameter in the postfix version.
Here is the code to demonstrate the same.
Before increment: i = 3 After pre increment: i = 4
Before increment: i = 3 After post increment: i = 3
Overloading the decrement operator
Similarly we can also overload the decrement operator as follows
Before decrement: i = 3 After pre decrement: i = 2
Before decrement: i = 3 After post decrement: i = 3
- Pre-increment (or pre-decrement) in C++
- Increment (Decrement) operators require L-value Expression
- Operator Overloading in C++
- Rules for operator overloading
- Overloading New and Delete operator in c++
- Types of Operator Overloading in C++
- Overloading Subscript or array index operator  in C++
- C++ Program to concatenate two strings using Operator Overloading
- Operator overloading in C++ to print contents of vector, map, pair, ..
- Pre-increment and Post-increment in C/C++
- Why overriding both the global new operator and the class-specific operator is not ambiguous?
- Function Overloading in C++
- Constructor Overloading in C++
- Function Overloading and float in C++
- Does overloading work with Inheritance?
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