GATE | GATE-CS-2015 (Set 1) | Question 65
Consider a system with byte-addressable memory, 32 bit logical addresses, 4 kilobyte page size and page table entries of 4 bytes each. The size of the page table in the system in megabytes is ___________
Number of entries in page table = 232 / 4Kbyte = 232 / 212 = 220 Size of page table = (No. page table entries)*(Size of an entry) = 220 * 4 bytes = 222 = 4 Megabytes
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