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GATE | GATE-CS-2014-(Set-3) | Question 65

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The above sequential circuit is built using JK flip-flops is initialized with Q2Q1Q0 = 000. The state sequence for this circuit for the next 3 clock cycle is

(A)

001, 010, 011

(B)

111, 110, 101

(C)

100, 110, 111

(D)

100, 011, 001



Answer: (C)

Explanation:

JK ff truth table—

jkQ
00Q0
101
010
11Q0’

Initially Q2Q1Q0=000 Present state FF input                   Next state

Q2Q1Q0J2K2J1K1J0K0Q2Q1Q0
000100101100
100101001110
110001011111
            

So ans is (C) part. 



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Last Updated : 29 Sep, 2021
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