Find letter’s position in Alphabet using Bit operation

Given a string of English alphabets. The task is, for every character in the string print its position in the English alphabets.

Note: The characters in the string are considered to be case-insensitive. That is, both ‘A’ and ‘a’ are at first position.

Examples:

Input: “Geeks”
Output: 7 5 5 11 19
‘G’ is the 7th character of the alphabets
‘e’ is the 5th and so on…

Input: “Algorithms”
Output: 1 12 7 15 18 9 20 8 13 19

Approach:
A letter’s position in Alphabet can easily be found by performing logical AND operation with the number 31.

Note that this is only applicable on letters and not special characters.

Every letter has an ASCII value which can be represented in binary form. Performing the bitwise and of this value with the number 31 will give the letter’s position in the alphabets.

Below is the implementation of the above approach:

C++

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// C++ implementation of the approach
#include <iostream>
using namespace std;
  
const int NUM = 31;
  
// Function to calculate the position
// of characters
void positions(string str, int n)
{
    for (int i = 0; i < n; i++) {
  
        // Performing AND operation
        // with number 31
        cout << (str[i] & NUM) << " ";
    }
}
  
// Driver code
int main()
{
    string str = "Geeks";
    int n = str.length();
  
    positions(str, n);
  
    return 0;
}

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Java














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// Java implementation of the approach 


public class GFG { 


  


    public static final int NUM = 31; 


  


    // Function to calculate the position 


    // of characters 


    static void positions(String str, int n) 


    { 


        for (int i = 0; i < n; i++) { 


  


            // Performing AND operation 


            // with number 31 


            System.out.print((str.charAt(i) & NUM) + " "); 


        } 


    } 


  


    // Driver code 


    public static void main(String[] args) 


    { 


        String str = "Geeks"; 


        int n = str.length(); 


        positions(str, n); 


    } 


} 



















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Python














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# Python3 implementation of the approach 


   


NUM = 31


   


# Function to calculate the position 


# of characters 


def positions(str): 


    for i in str: 


           


        # Performing AND operation 


        # with number 31 


        print((ord(i) & NUM), end =" ") 


   


# Driver code 


str = "Geeks"


positions(str) 



















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C#














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// C# implementation of the approach 


using System; 


  


class GFG { 


  


    public static int NUM = 31; 


  


    // Function to calculate the position 


    // of characters 


    static void positions(string str, int n) 


    { 


        for (int i = 0; i < n; i++) { 


  


            // Performing AND operation 


            // with number 31 


            Console.Write((str[i] & NUM) + " "); 


        } 


    } 


  


    // Driver code 


    public static void Main() 


    { 


        string str = "Geeks"; 


        int n = str.Length; 


        positions(str, n); 


    } 


} 


  


// This code is contributed by AnkitRai01 



















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PHP














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<?php 


// PHP implementation of the approach 


  


// Function to calculate the position 


// of characters 


function positions($str, $n) 


{ 


    $a = 31; 


    for ($i = 0; $i < $n; $i++)  


    { 


  


        // Performing AND operation 


        // with number 31$ 


        print((ord($str[$i])&($a))." "); 


    } 


} 


  


// Driver code 


$str = "Geeks"; 


$n = strlen($str); 


positions($str, $n); 


  


// This code is contributed by 29AjayKumar 


?> 



















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Output:


7 5 5 11 19






          
          
          
          

            

    

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