Given a string of English alphabets. The task is, for every character in the string print its position in the English alphabets.
Note: The characters in the string are considered to be case-insensitive. That is, both ‘A’ and ‘a’ are at first position.
Output: 7 5 5 11 19
‘G’ is the 7th character of the alphabets
‘e’ is the 5th and so on…
Output: 1 12 7 15 18 9 20 8 13 19
A letter’s position in Alphabet can easily be found by performing logical AND operation with the number 31.
Note that this is only applicable on letters and not special characters.
Every letter has an ASCII value which can be represented in binary form. Performing the bitwise and of this value with the number 31 will give the letter’s position in the alphabets.
Below is the implementation of the above approach:
7 5 5 11 19
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- Generate number with given operation and check if it is palindrome
- Sub-string that contains all lowercase alphabets after performing the given operation
- Check whether the string S1 can be made equal to S2 with the given operation
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