Given an array where every element occurs a times, except one element which occurs b (a>b) times. Find the element that occurs b times.
Input : arr = [1, 1, 2, 2, 2, 3, 3, 3] a = 3, b = 2 Output : 1
Add each number once and multiply the sum by a, we will get a times the sum of each element of the array. Store it as a_sum. Subtract the sum of the whole array from the a_sum and divide the result by (a-b). The number we get is the required number (which appears b times in the array).
Please refer below article for more approaches.
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