Output of following program?
# include <stdio.h> void fun(int *ptr) { *ptr = 30; } int main() { int y = 20; fun(&y); printf("%d", y); return 0; } |
(A) 20
(B) 30
(C) Compiler Error
(D) Runtime Error
Answer: (B)
Explanation: The function fun() expects a pointer ptr to an integer (or an address of an integer). It modifies the value at the address ptr. The dereference operator * is used to access the value at an address. In the statement ‘*ptr = 30’, value at address ptr is changed to 30. The address operator & is used to get the address of a variable of any data type. In the function call statement ‘fun(&y)’, address of y is passed so that y can be modified using its address.
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