C++ | Inheritance | Question 1

#include<iostream> 
   
using namespace std; 
class Base1 { 
 public: 
     Base1() 
     { cout << " Base1's constructor called" << endl;  } 
}; 
   
class Base2 { 
 public: 
     Base2() 
     { cout << "Base2's constructor called" << endl;  } 
}; 
   
class Derived: public Base1, public Base2 { 
   public: 
     Derived() 
     {  cout << "Derived's constructor called" << endl;  } 
}; 
   
int main() 
{ 
   Derived d; 
   return 0; 
} 

(A) Compiler Dependent

(B) Base1′s constructor called
Base2′s constructor called
Derived’s constructor called

(C) Base2′s constructor called
Base1′s constructor called
Derived’s constructor called

(D) Compiler Error

Answer: (B)

Explanation: When a class inherits from multiple classes, constructors of base classes are called in the same order as they are specified in inheritance.

Quiz of this Question

Attention reader! Don’t stop learning now. Get hold of all the important DSA concepts with the DSA Self Paced Course at a student-friendly price and become industry ready.

My Personal Notes

Recommended Posts: