C++ | Exception Handling | Question 12

What happens when a function throws an error but doesn’t specify it in the list of exceptions it can throw.

For example, what is the output of following program?

filter_none

edit
close

play_arrow

link
brightness_4
code

#include <iostream>
using namespace std;
  
// Ideally it should have been "int fun() (int)"
int fun()
{
    throw 10;
}
  
int main()
{
    try
    {
        fun();
    }
    catch (int )
    {
        cout << "Caught";
    }
    return 0;
}

chevron_right






                        filter_none








(A) Compiler Error

(B) No compiler Error. Output is “Caught”



 Answer: (B) 

Explanation: C++ compiler doesn’t check enforce a function to list the exceptions that it can throw. In Java, it is enforced.


        
          
          
          
        

            

It is up to the programmer to specify. Being a civilized programmer, a programmer should specify the list.

Quiz of this Question



          
          
          
          

            

    

        My Personal Notes
        arrow_drop_up
    

    

        
        

            
            
        

    


Recommended Posts: