C | Advanced Pointer | Question 10

Output of following program

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#include <stdio.h>
int fun(int arr[]) {
   arr = arr+1; 
   printf("%d ", arr[0]);
}
int main(void) {
   int arr[2] = {10, 20};
   fun(arr);
   printf("%d", arr[0]);
   return 0;
}

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(A) Compiler Error
(B) 20 10
(C) 20 20
(D) 10 10


Answer: (B)

Explanation: In C, array parameters are treated as pointers (See https://www.geeksforgeeks.org/why-c-treats-array-parameters-as-pointers/ for details).

So the variable arr represents an array in main(), but a pointer in fun().

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