# Array formed from difference of each element from the largest element in the given array

Given an array arr[], the task is to find the array formed from the difference of each element from the largest element in the given array.

Example:

Input: arr[] = {3, 6, 9, 2,6}
Output: {6, 3, 0, 7, 3}
Explanation:
Largest element of the array = 9
Therefore difference of arr[i] from 9:
Element 1: 9 – 3 = 6
Element 2: 9 – 6 = 3
Element 3: 9 – 9 = 0
Element 4: 9 – 2 = 7
Element 5: 9 – 6 = 3
Hence the output will be {6, 3, 0, 7, 3}

Input: arr[] = {7, 2, 5, 6, 3, 1, 6, 9}
Output: {2, 7, 4, 3, 6, 8, 3, 0}

Approach:
Find the largest of n elements in an array and store it in a variable largest. Now check the difference between the largest and the other elements in the array.

Below is the implementation of the above approach:

## C++

 `// C++ program to find the array formed` `// from the difference of each element ` `// from the largest element in the given array`   `#include ` `using` `namespace` `std;` `int` `difference(``int` `arr[], ``int` `n)` `{` `    ``// Initializing current largest ` `    ``// as the first element.` `    ``int` `largest = arr[0];` `    ``int` `i;`   `    ``// For loop to compute ` `    ``// the largest element` `    ``for` `(i = 0; i < n; i++) {`   `        ``// Checking if the current element ` `        ``// is greater than the defined largest` `        ``if` `(largest < arr[i])` `            ``largest = arr[i];` `    ``}`   `    ``// For loop to replace the elements ` `    ``// in the array with the difference ` `    ``for` `(i = 0; i < n; i++)` `        ``arr[i] = largest - arr[i];`   `    ``// For loop to print the elements` `    ``for` `(i = 0; i < n; i++)` `        ``cout << arr[i] << ``" "``;` `}`   `// Driver code` `int` `main()` `{` `    ``int` `arr[] = { 10, 5, 9, 3, 2 };` `    ``int` `n = ``sizeof``(arr) / ``sizeof``(arr[0]);` `    ``difference(arr, n);` `    ``return` `0;` `}`

## Java

 `// Java program to find the array formed` `// from the difference of each element ` `// from the largest element in the given array` `import` `java.util.*;`   `class` `GFG` `{` `static` `void` `difference(``int` `arr[], ``int` `n)` `{` `    ``// Initializing current largest ` `    ``// as the first element.` `    ``int` `largest = arr[``0``];` `    ``int` `i;`   `    ``// For loop to compute ` `    ``// the largest element` `    ``for` `(i = ``0``; i < n; i++)` `    ``{`   `        ``// Checking if the current element ` `        ``// is greater than the defined largest` `        ``if` `(largest < arr[i])` `            ``largest = arr[i];` `    ``}`   `    ``// For loop to replace the elements ` `    ``// in the array with the difference ` `    ``for` `(i = ``0``; i < n; i++)` `        ``arr[i] = largest - arr[i];`   `    ``// For loop to print the elements` `    ``for` `(i = ``0``; i < n; i++)` `        ``System.out.print(arr[i] + ``" "``);` `}`   `// Driver code` `public` `static` `void` `main(String[] args)` `{` `    ``int` `arr[] = { ``10``, ``5``, ``9``, ``3``, ``2` `};` `    ``int` `n = arr.length;` `    ``difference(arr, n);` `}` `}`   `// This code is contributed by 29AjayKumar`

## Python3

 `# Python3 program to find the array formed` `# from the difference of each element ` `# from the largest element in the given array` `def` `difference(arr, n):` `    `  `    ``# Initializing current largest` `    ``# as the first element.` `    ``largest ``=` `arr[``0``];` `    ``i ``=` `0``;`   `    ``# For loop to compute` `    ``# the largest element` `    ``for` `i ``in` `range``(n):`   `        ``# Checking if the current element` `        ``# is greater than the defined largest` `        ``if` `(largest < arr[i]):` `            ``largest ``=` `arr[i];` `    `  `    ``# For loop to replace the elements` `    ``# in the array with the difference` `    ``for` `i ``in` `range``(n):` `        ``arr[i] ``=` `largest ``-` `arr[i];`   `    ``# For loop to print the elements` `    ``for` `i ``in` `range``(n):` `        ``print``(arr[i], end ``=` `" "``);`   `# Driver code` `if` `__name__ ``=``=` `'__main__'``:` `    ``arr ``=` `[ ``10``, ``5``, ``9``, ``3``, ``2` `];` `    ``n ``=` `len``(arr);` `    ``difference(arr, n);`   `# This code is contributed by Rajput-Ji`

## C#

 `// C# program to find the array formed` `// from the difference of each element ` `// from the largest element in the given array` `using` `System;`   `class` `GFG` `{` `    `  `static` `void` `difference(``int` `[]arr, ``int` `n)` `{` `    ``// Initializing current largest ` `    ``// as the first element.` `    ``int` `largest = arr[0];` `    ``int` `i;`   `    ``// For loop to compute ` `    ``// the largest element` `    ``for` `(i = 0; i < n; i++)` `    ``{`   `        ``// Checking if the current element ` `        ``// is greater than the defined largest` `        ``if` `(largest < arr[i])` `            ``largest = arr[i];` `    ``}`   `    ``// For loop to replace the elements ` `    ``// in the array with the difference ` `    ``for` `(i = 0; i < n; i++)` `        ``arr[i] = largest - arr[i];`   `    ``// For loop to print the elements` `    ``for` `(i = 0; i < n; i++)` `        ``Console.Write(arr[i] + ``" "``);` `}`   `// Driver code` `public` `static` `void` `Main(String[] args)` `{` `    ``int` `[]arr = { 10, 5, 9, 3, 2 };` `    ``int` `n = arr.Length;` `    ``difference(arr, n);` `}` `}`   `// This code is contributed by PrinciRaj1992`

## Javascript

 ``

Output:

`0 5 1 7 8`

Time complexity: O(n)
Auxiliary space: O(1)

Feeling lost in the world of random DSA topics, wasting time without progress? It's time for a change! Join our DSA course, where we'll guide you on an exciting journey to master DSA efficiently and on schedule.
Ready to dive in? Explore our Free Demo Content and join our DSA course, trusted by over 100,000 geeks!

Previous
Next