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Aptitude | Probability | Question 8

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A 5 digit number is formed by using digits 1, 2, 3, 4 and 5 with no two digits same. What is the probability that the formed number is divisible by 4? (A) 1/5 (B) 4/5 (C) 3/5 (D) 1/4

Answer: (A)

Explanation: To be divisible by 4, the number has to end with the last two digits forming a number divisible by 4. Since there are only 5 digits: 1, 2, 3, 4, 5. So, possible last two digits according to divisibility by 4: 12 24 32 52 For each of them we now have to put the remaining numbers in front: 3x2x1, therefore 6 combinations for each number set = 6×4 (we have 4 sets from above) = 24. So, required probability is: P = Number of desired outcomes / number of possible outcomes = 24 /(5*4*3*2*1) = 24 / (5!) = 24 / 120 = 1/5 So, option (A) is correct.

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Last Updated : 11 Sep, 2018
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