isnormal() in C++
Last Updated :
26 Jun, 2023
This function is defined in <cmath.h> . By using isnormal() function, we determines that whether the given number is normal (neither zero, infinite nor NAN) or not. This function returns 1 if the number is normal else return zero.
Syntax:
bool isnormal(float x);
or
bool isnormal(double x);
or
bool isnormal(long double x);
Parameters: This functions takes a mandatory parameter x which represents the floating point value.
Returns: If the given value is normal then the function returns 1 otherwise the function returns zero.
Time Complexity: O(1)
Auxiliary Space: O(1)
Below program illustrate the isnormal() function in C++:
Example 1:- To show with float value
cpp
#include <bits/stdc++.h>
using namespace std;
int main()
{
float f = 7.0F;
cout << "isnormal(7.0) is = " << isnormal(f) << endl;
f = 0.0F;
cout << "isnormal(0.0) is = " << isnormal(f) << endl;
f = 9.2F;
cout << "isnormal(9.2/0.0) is = " << isnormal(f / 0.0) << endl;
return 0;
}
|
Output:
isnormal(7.0) is = 1
isnormal(0.0) is = 0
isnormal(9.2/0.0) is = 0
Example 2:- To show with double value
cpp
#include <bits/stdc++.h>
using namespace std;
int main()
{
double f = 7.0;
cout << "isnormal(7.0) is = " << isnormal(f) << endl;
f = 0.0;
cout << "isnormal(0.0) is = " << isnormal(f) << endl;
f = 9.2;
cout << "isnormal(9.2/0.0) is = " << isnormal(f / 0.0) << endl;
return 0;
}
|
Output:
isnormal(7.0) is = 1
isnormal(0.0) is = 0
isnormal(9.2/0.0) is = 0
Example 3:- To show with long double value
cpp
#include <bits/stdc++.h>
using namespace std;
int main()
{
long double f = 7.0;
cout << "isnormal(7.0) is = " << isnormal(f) << endl;
f = 0.0;
cout << "isnormal(0.0) is = " << isnormal(f) << endl;
f = 9.2;
cout << "isnormal(9.2/0.0) is = " << isnormal(f / 0.0) << endl;
return 0;
}
|
Output:
isnormal(7.0) is = 1
isnormal(0.0) is = 0
isnormal(9.2/0.0) is = 0
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