Which one of the following options is CORRECT given three positive integers x, y and z, and a predicate?
P(x) = ¬(x=1)∧∀y(∃z(x=y*z)⇒(y=x)∨(y=1))
(A)
P(x) being true means that x is a number other than 1
(B)
P(x) is always true irrespective of the value of x
(C)
P(x) being true means that x has exactly two factors other than 1 and x
(D)
P(x) being true means that x is a prime number
Answer
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