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UGC-NET | UGC NET CS 2018 July – II | Question 95
  • Difficulty Level : Medium
  • Last Updated : 20 Nov, 2018

The hexadecimal equivalent of the binary integer number 110101101 is:
(A) D24
(B) 1BD
(C) 1AE
(D) 1AD


Answer: (D)

Explanation: Group the given number in subgroup of 4 from right and assign alphabet when it exceeds 1001:
1010 – A
1011 – B
1100 – C
1101 – D
1110 – E
1111 – F
Given number is 110101101:
1101 – D
1010 – A
1 – 1
Hexadecimal equivalent iss 1AD.
So, option (D) is correct.


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