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UGC-NET | UGC NET CS 2018 July - II | Question 4
What is the output of the following ‘C’ program ? (Assuming little - endian representation of multi-byte data in which Least Significant Byte (LSB) is stored at the lowest memory address.)
#include <stdio.h>
#include <stdlib.h>
/ * Assume short int occupies two bytes of storage */
int main ( )
{
union saving
{
short int one;
char two[2];
};
union saving m;
m.two [0] = 5;
m.two [1] = 2;
printf(’’%d, %d, %d\\n”, m.two [0], m.two [1], m.one);
}/ * end of main * /
(A)
5, 2, 1282
(B)
5, 2, 52
(C)
5, 2, 25
(D)
5, 2, 517
Answer
Please comment below if you find anything wrong in the above post
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