Skip to content
Related Articles

Related Articles

UGC-NET | UGC NET CS 2015 Dec – II | Question 28
  • Last Updated : 02 May, 2018
GeeksforGeeks - Summer Carnival Banner

Consider a disk with 16384 bytes per track having a rotation time of 16 msec and average seek time of 40 msec. What is the time in msec to read a block of 1024 bytes from this disk?
(A) 57 sec
(B) 49 sec
(C) 48 sec
(D) 17 sec


Answer: (B)

Explanation: Transfer time(TT) = ((1024 bytes * 16 ms) / (16384 bytes )) = 1 msec
Rotational latency = 16 msec / 2 = 8 msec
seek time = 40 msec.
total time = seek time + rotational latency + transfer time
= 40 + 8 + 1 = 49 msec
So, option (B) is correct.

Quiz of this Question

Attention reader! Don’t stop learning now. Get hold of all the important DSA concepts with the DSA Self Paced Course at a student-friendly price and become industry ready.

My Personal Notes arrow_drop_up
Recommended Articles
Page :