Consider a disk with 16384 bytes per track having a rotation time of 16 msec and average seek time of 40 msec. What is the time in msec to read a block of 1024 bytes from this disk?
(A) 57 sec
(B) 49 sec
(C) 48 sec
(D) 17 sec
Explanation: Transfer time(TT) = ((1024 bytes * 16 ms) / (16384 bytes )) = 1 msec
Rotational latency = 16 msec / 2 = 8 msec
seek time = 40 msec.
total time = seek time + rotational latency + transfer time
= 40 + 8 + 1 = 49 msec
So, option (B) is correct.
Quiz of this Question
Attention reader! Don’t stop learning now. Get hold of all the important DSA concepts with the DSA Self Paced Course at a student-friendly price and become industry ready.