QA – Placement Quizzes | Trigonometry & Height and Distances | Question 7
From a point P on a level ground, the angle of elevation of the top of a tower is 30 degrees. If the tower is 100 m high, the distance of point P from the foot of the tower is:
(A) 149 m
(B) 156 m
(C) 173 m
(D) 200 m
Explanation: Let QR be the tower. Then,
QR = 100 m and angle QPR = 30 degrees.
We know, cot 30° = √3 = PQ/QR.
Therefore, PQ = 100*√3 = 173 m.
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