Out of 7 boys and 4 girls, how many queues of 3 boys and 2 girls can be formed?
Explanation: Number of ways to choose 3 boys out of 7 = 7C3.
Number of ways to choose 2 girls out of 4 = 4C2.
Therefore, number of ways to choose the required groups = 7C3 * 4C2 = 35 * 6 = 210.
Number of ways to arrange the 3 boys and 2 girls in a queue = 5! = 120.
Therefore, the required number of queues = 210 * 120 = 25200.
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