# QA – Placement Quizzes | Mensuration 2D | Question 10

If the radius of a circle is increased by 6%, then the area is increased by:**(A)** 14.96**(B)** 11.24**(C)** 13.64**(D)** 12.36**Answer:** **(D)****Explanation:** New Area of the Circle = Pi * (R + 6% of R)^2

= Pi * (R + 0.06R)^2

= Pi * (1.06R)^2

= Pi * R^2 * (1.06)^2.

Therefore, percentage increase in Area = [ Pi * R^2 * (1.06)^2 – Pi * R^2 ]/ (Pi * R^2)

= 1.06^2 – 1 = 0.1236 = 12.36%

Quiz of this Question

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