Find the output of the following program:
Python3
L1 = [1, 1.33, 'GFG', 0, 'NO', None, 'G', True]
val1, val2 = 0,''
for x in L1:
if(type(x) == int or type(x) == float):
val1 += x
elif(type(x) == str):
val2 += x
else:
break
print(val1, val2)
|
(A)
2 GFGNO
(B)
2.33 GFGNOG
(C)
2.33 GFGNONoneGTrue
(D)
2.33 GFGNO
Answer: (D)
Explanation:
val1 will only have integer and floating values val1 = 1 + 1.33 + 0 = 2.33 and val2 will have string values val2 =’GFG’ + ‘NO’ = ‘GFGNO’. String ‘G’ will not be part of val2 as the for loop will break at None, thus ‘G’ will not be added to val2.
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