Find the output of the following program:
Python3
L1 = [ 1 , 1.33 , 'GFG' , 0 , 'NO' , None , 'G' , True ]
val1, val2 = 0 ,''
for x in L1:
if ( type (x) = = int or type (x) = = float ):
val1 + = x
elif ( type (x) = = str ):
val2 + = x
else :
break
print (val1, val2)
|
(A)
2 GFGNO
(B)
2.33 GFGNOG
(C)
2.33 GFGNONoneGTrue
(D)
2.33 GFGNO
Answer: (D)
Explanation:
val1 will only have integer and floating values val1 = 1 + 1.33 + 0 = 2.33 and val2 will have string values val2 =’GFG’ + ‘NO’ = ‘GFGNO’. String ‘G’ will not be part of val2 as the for loop will break at None, thus ‘G’ will not be added to val2.
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