Java | Abstract Class and Interface | Question 3
Predict the output of the following program.
abstract class demo{ public int a; demo() { a = 10; } abstract public void set(); abstract final public void get(); } class Test extends demo{ public void set(int a) { this.a = a; } final public void get() { System.out.println("a = " + a); } public static void main(String[] args) { Test obj = new Test(); obj.set(20); obj.get(); }} |
(A) a = 10
(B) a = 20
(C) Compilation error
Answer: (C)
Explanation: Final method can’t be overridden. Thus, an abstract function can’t be final.
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