ISRO | ISRO CS 2009 | Question 77

If the mean of a normal frequency distribution of 1000 items is 25 and its standard deviation is 2.5, then its maximum ordinate is
(A) (1000/√2π).e^{-25
(B) 1000/√2π
(C) (1000/√2π ).e_-2.5}
(D) 400/√2π


Answer: (D)

Explanation: The maximum ordinate of a normal distribution is given by 1 / σ √2π
where, σ is the standard variation
maximum ordinate = 1000 x (1 / σ √2π) = 1000 / σ √2π = 400 / √2π

Option (D) is correct.

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