GATE | GATE MOCK 2017 | Question 22
What will be the output produced by the following C code:
int main()
{
int array[5][5];
printf("%d",( (array == *array) && (*array == array[0]) ));
return 0;
}
(A) 1
(B) 0
(C) 2
(D) -1
Answer: (A)
Explanation:
Given is a 2d array array[5][5].
Suppose base address of array is 2000
array = 2000
*array = 2000
array[0] = 2000
So expression is something like 2000==2000 && 2000==2000 i.e. 1&&1 will return 1.
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Last Updated :
28 Jun, 2021
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