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GATE | GATE IT 2006 | Question 32
  • Last Updated : 02 May, 2016

Let L be a context-free language and M a regular language. Then the language L ∩ M is
(A) always regular
(B) never regular
(C) always a deterministic context-free language
(D) always a context-free language

Answer: (D)


L is a context free language and M is a regular language, hence context free as well. Therefore, L ∩ M is context free for sure, according to closure laws of context free languages. We need to check whether it would be regular or non-regular always. We can prove that by giving examples s.t. L ∩ M can be regular and non-regular both.
• L = {anbn |n ≥ 0} and M = a*b*, in this case L ∩ M will be L itself, hence context free but not regular. L ∩ M won’t be deterministic CFL everytime either, like in this example.
L = {anbn |n ≥ 0} and M = a, in this case L ∩ M will be M itself, hence regular.

Considering the above statement, correct answer would be (D) always a context-free language.


This solution is contributed by vineet purswani .

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