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GATE | GATE-IT-2004 | Question 77

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  • Last Updated : 20 Mar, 2018
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Consider the following schedule S of transactions T1 and T2:

Read(A)A = A – 10Read (A)Temp = 0.2*A



B = B + 10
B = B + TempWrite(B)

(A) S is serializable only as T1, T2
(B) S is serializable only as T2, T1
(C) S is serializable both as T1, T2 and T2, T1
(D) S is serializable either as T1 or as T2
(E) None of these

Answer: (E)

Explanation: This given schedule is not serializable as cycles exist in precedence graph .Therefore, options A, B, C, D are practically not possible.

The answer should be schedule is NOTĀ serializable both as T2,T1 and T1,T2


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