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GATE | GATE-CS-2014-(Set-3) | Question 65

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The above sequential circuit is built using JK flip-flops is initialized with Q2Q1Q0 = 000. The state sequence for this circuit for the next 3 clock cycle is

(A)

001, 010, 011

(B)

111, 110, 101

(C)

100, 110, 111

(D)

100, 011, 001



Answer: (C)

Explanation:

JK ff truth table—

j k Q
0 0 Q0
1 0 1
0 1 0
1 1 Q0’

Initially Q2Q1Q0=000 Present state FF input                   Next state

Q2 Q1 Q0 J2 K2 J1 K1 J0 K0 Q2 Q1 Q0
0 0 0 1 0 0 1 0 1 1 0 0
1 0 0 1 0 1 0 0 1 1 1 0
1 1 0 0 0 1 0 1 1 1 1 1
                       

So ans is (C) part. 


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Last Updated : 29 Sep, 2021
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