GATE | GATE CS 2011 | Question 65
Let the page fault service time be 10ms in a computer with average memory access time being 20ns. If one page fault is generated for every 10^6 memory accesses, what is the effective access time for the memory?
Let P be the page fault rate Effective Memory Access Time = p * (page fault service time) + (1 - p) * (Memory access time) = ( 1/(10^6) )* 10 * (10^6) ns + (1 - 1/(10^6)) * 20 ns = 30 ns (approx)
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