GATE | GATE CS 2011 | Question 15ReadDiscussCoursesPracticeImprove Article ImproveSave Article SaveLike Article LikeThe minimum number of D flip-flops needed to design a mod-258 counter is.(A) 9(B) 8(C) 512(D) 258Answer: (A)Explanation:An n-bit binary counter consists of n flip-flops and can count in binary from 0 to 2^n – 1.  (Source: Computer System Architecture by Morris Mano) 2^n ≥ 258Quiz of this QuestionLast Updated : 29 Sep, 2021Like Article Save Article Please Login to comment...