GATE | GATE-CS-2009 | Question 6ReadDiscussCoursesPracticeImprove Article ImproveSave Article SaveLike Article LikeWhat is the minimum number of gates required to implement the Boolean function (AB+C)if we have to use only 2-input NOR gates?(A) 2(B) 3(C) 4(D) 5Answer: (B)Explanation: AB+C = (A+C)(B+C) = ((A+C)’ + (B+C)’)’So, ‘3’ 2-input NOR gates are required.Quiz of this QuestionLast Updated : 19 Nov, 2018Like Article Save Article Please Login to comment...