GATE | GATE-CS-2006 | Question 85
Given two three bit numbers a2a1a0 and b2b1b0 and c, the carry in, the function that represents the carry generate function when these two numbers are added is:
Explanation: For carry look ahead adder we know carry generate function—
As we are having two 3 bits number to add so final carry out will be C3-
Putting value of Pi,Gi in 3
C3=(A2.B2)+(A1.B1)(A2+B2)+(A0.B0)(A1+B1)(A2+B2) (TAKING C0=0)
SO ANS IS (A) PART.
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